8(1-x)=-2x-40

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Solution for 8(1-x)=-2x-40 equation: 



8(1-x)=-2x-40

We move all terms to the left:

8(1-x)-(-2x-40)=0

We add all the numbers together, and all the variables

8(-1x+1)-(-2x-40)=0

We multiply parentheses

-8x-(-2x-40)+8=0

We get rid of parentheses

-8x+2x+40+8=0

We add all the numbers together, and all the variables

-6x+48=0

We move all terms containing x to the left, all other terms to the right

-6x=-48

x=-48/-6

x=+8

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