2y+3-2(2y+5)=4(y-2)

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Solution for 2y+3-2(2y+5)=4(y-2) equation: 



2y+3-2(2y+5)=4(y-2)

We move all terms to the left:

2y+3-2(2y+5)-(4(y-2))=0

We multiply parentheses

2y-4y-(4(y-2))-10+3=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We add all the numbers together, and all the variables

-2y-(4y-8)-7=0

We get rid of parentheses

-2y-4y+8-7=0

We add all the numbers together, and all the variables

-6y+1=0

We move all terms containing y to the left, all other terms to the right

-6y=-1

y=-1/-6

y=1/6

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