2y+3(2y-3)+2=33

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Solution for 2y+3(2y-3)+2=33 equation: 



2y+3(2y-3)+2=33

We move all terms to the left:

2y+3(2y-3)+2-(33)=0

We add all the numbers together, and all the variables

2y+3(2y-3)-31=0

We multiply parentheses

2y+6y-9-31=0

We add all the numbers together, and all the variables

8y-40=0

We move all terms containing y to the left, all other terms to the right

8y=40

y=40/8

y=5

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