(1/3)x-(2/3)=(1/6)

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Solution for (1/3)x-(2/3)=(1/6) equation: 



(1/3)x-(2/3)=(1/6)

We move all terms to the left:

(1/3)x-(2/3)-((1/6))=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)x-(+2/3)-((+1/6))=0

We multiply parentheses

x^2-(+2/3)-((+1/6))=0

We get rid of parentheses

x^2-2/3-((+1/6))=0

We calculate fractions


x^2+()/()+()/()=0

We add all the numbers together, and all the variables

x^2+2=0

a = 1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·1·2
Δ = -8
Delta is less than zero, so there is no solution for the equation

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