2y+16+y+42=2(10y+75)

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Solution for 2y+16+y+42=2(10y+75) equation: 



2y+16+y+42=2(10y+75)

We move all terms to the left:

2y+16+y+42-(2(10y+75))=0

We add all the numbers together, and all the variables

3y-(2(10y+75))+58=0



We calculate terms in parentheses: -(2(10y+75)), so:

2(10y+75)

We multiply parentheses

20y+150

Back to the equation:

-(20y+150)



We get rid of parentheses

3y-20y-150+58=0

We add all the numbers together, and all the variables

-17y-92=0

We move all terms containing y to the left, all other terms to the right

-17y=92

y=92/-17

y=-5+7/17

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