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2y(y-1)-2=y
We move all terms to the left:
2y(y-1)-2-(y)=0
We add all the numbers together, and all the variables
-1y+2y(y-1)-2=0
We multiply parentheses
2y^2-1y-2y-2=0
We add all the numbers together, and all the variables
2y^2-3y-2=0
a = 2; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·2·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-5}{2*2}=\frac{-2}{4} =-1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+5}{2*2}=\frac{8}{4} =2 $
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