F(x)=2(x-5+5)+8

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Solution for F(x)=2(x-5+5)+8 equation: 



(F)=2(F-5+5)+8

We move all terms to the left:

(F)-(2(F-5+5)+8)=0

We add all the numbers together, and all the variables

F-(2(+F)+8)=0



We calculate terms in parentheses: -(2(+F)+8), so:

2(+F)+8

We multiply parentheses

2F+8

Back to the equation:

-(2F+8)



We get rid of parentheses

F-2F-8=0

We add all the numbers together, and all the variables

-1F-8=0

We move all terms containing F to the left, all other terms to the right

-F=8

F=8/-1

F=-8

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