2y(y+15y)=180

Solution for 2y(y+15y)=180 equation:

2y(y+15y)=180

We move all terms to the left:

2y(y+15y)-(180)=0

We add all the numbers together, and all the variables

2y(+16y)-180=0

We multiply parentheses

32y^2-180=0

a = 32; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·32·(-180)
Δ = 23040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23040}=\sqrt{2304*10}=\sqrt{2304}*\sqrt{10}=48\sqrt{10}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{10}}{2*32}=\frac{0-48\sqrt{10}}{64}
=-\frac{48\sqrt{10}}{64}
=-\frac{3\sqrt{10}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{10}}{2*32}=\frac{0+48\sqrt{10}}{64}
=\frac{48\sqrt{10}}{64}
=\frac{3\sqrt{10}}{4}
$