10((12y-47)/10)=12y-32

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Solution for 10((12y-47)/10)=12y-32 equation: 



10((12y-47)/10)=12y-32

We move all terms to the left:

10((12y-47)/10)-(12y-32)=0

We get rid of parentheses

10((12y-47)/10)-12y+32=0

We multiply all the terms by the denominator


10((12y-47)-12y*10)+32*10)=0

We add all the numbers together, and all the variables

10((12y-47)-12y*10)=0

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