If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x=x2
We move all terms to the left:
2x-(x2)=0
We add all the numbers together, and all the variables
-1x^2+2x=0
a = -1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-1}=\frac{-4}{-2} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-1}=\frac{0}{-2} =0 $
| 240=-8(-5v+5) | | -9+n/13+10=8 | | 4-2.5(1+6.5x)=21 | | m^2+10m+70=0 | | -n+9+4n=6n+10 | | -5n+9-3n=-4(2+n) | | 6(2n-1)=12n-6 | | 15+n-6n=7n+3n | | 15x^2+25x-7=0 | | 0.4(2x+0.3)=1/3(6x−7.2) | | 11/3x-14=1/2(3x-8) | | 43x+-3x=240 | | (2x+3)^2=13 | | -3(y-1+8(y-3)=6y+7-5y | | 2^x+2+2^x+6=0 | | t/2+3=t/8-1 | | -3(a+17)=(3a-5) | | 2(3r-4)+2(2r+1)=24 | | 14=13y=21-20y | | 2(4x-3)=2(3x-5) | | B=4a+9a^2 | | 4x/5+1/5=5 | | 7*(x-4)+2*(x+3)=3*(x+5)-1 | | 3x^2+7x-15=x-3 | | 3x+4-(x+6)=10x+12 | | r+1÷2=3/4 | | r+1/2=3/4 | | 2x/4=5/8 | | 4x-7=5x+39=3x+12 | | 3x/2+1/2=5 | | 2x-(-3+9-1)+2=x-(x) | | r/7=31/7 |