7*(x-4)+2*(x+3)=3*(x+5)-1

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Solution for 7*(x-4)+2*(x+3)=3*(x+5)-1 equation: 



7(x-4)+2(x+3)=3(x+5)-1

We move all terms to the left:

7(x-4)+2(x+3)-(3(x+5)-1)=0

We multiply parentheses

7x+2x-(3(x+5)-1)-28+6=0



We calculate terms in parentheses: -(3(x+5)-1), so:

3(x+5)-1

We multiply parentheses

3x+15-1

We add all the numbers together, and all the variables

3x+14

Back to the equation:

-(3x+14)



We add all the numbers together, and all the variables

9x-(3x+14)-22=0

We get rid of parentheses

9x-3x-14-22=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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