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2x=6+2(x+3)
We move all terms to the left:
2x-(6+2(x+3))=0
We calculate terms in parentheses: -(6+2(x+3)), so:We get rid of parentheses
6+2(x+3)
determiningTheFunctionDomain 2(x+3)+6
We multiply parentheses
2x+6+6
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
2x-2x-12=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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