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2x=3x-9/4x-6
We move all terms to the left:
2x-(3x-9/4x-6)=0
Domain of the equation: 4x-6)!=0We get rid of parentheses
x∈R
2x-3x+9/4x+6=0
We multiply all the terms by the denominator
2x*4x-3x*4x+6*4x+9=0
Wy multiply elements
8x^2-12x^2+24x+9=0
We add all the numbers together, and all the variables
-4x^2+24x+9=0
a = -4; b = 24; c = +9;
Δ = b2-4ac
Δ = 242-4·(-4)·9
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12\sqrt{5}}{2*-4}=\frac{-24-12\sqrt{5}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12\sqrt{5}}{2*-4}=\frac{-24+12\sqrt{5}}{-8} $
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