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(9j)9/j=24/32(9j)
We move all terms to the left:
(9j)9/j-(24/32(9j))=0
Domain of the equation: j!=0
j∈R
Domain of the equation: 329j)!=0We add all the numbers together, and all the variables
j!=0/1
j!=0
j∈R
9j9/j-(+24/329j)=0
We get rid of parentheses
9j9/j-24/329j=0
We calculate fractions
We do not support ejpression: j^10
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