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5x^2+57x-36=0
a = 5; b = 57; c = -36;
Δ = b2-4ac
Δ = 572-4·5·(-36)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-63}{2*5}=\frac{-120}{10} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+63}{2*5}=\frac{6}{10} =3/5 $
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