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2x=3+2x^2
We move all terms to the left:
2x-(3+2x^2)=0
We get rid of parentheses
-2x^2+2x-3=0
a = -2; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·(-2)·(-3)
Δ = -20
Delta is less than zero, so there is no solution for the equation
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