(p+3)(3p-2)=0

Solution for (p+3)(3p-2)=0 equation:

(p+3)(3p-2)=0

We multiply parentheses ..

(+3p^2-2p+9p-6)=0

We get rid of parentheses

3p^2-2p+9p-6=0

We add all the numbers together, and all the variables

3p^2+7p-6=0

a = 3; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·3·(-6)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-11}{2*3}=\frac{-18}{6}
=-3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+11}{2*3}=\frac{4}{6}
=2/3
$