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2x=(3x-1)+(3x+1)
We move all terms to the left:
2x-((3x-1)+(3x+1))=0
We calculate terms in parentheses: -((3x-1)+(3x+1)), so:We add all the numbers together, and all the variables
(3x-1)+(3x+1)
We get rid of parentheses
3x+3x-1+1
We add all the numbers together, and all the variables
6x
Back to the equation:
-(6x)
-4x=0
x=0/-4
x=0
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