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12x-9=(8x-3)+3x
We move all terms to the left:
12x-9-((8x-3)+3x)=0
We calculate terms in parentheses: -((8x-3)+3x), so:We get rid of parentheses
(8x-3)+3x
We add all the numbers together, and all the variables
3x+(8x-3)
We get rid of parentheses
3x+8x-3
We add all the numbers together, and all the variables
11x-3
Back to the equation:
-(11x-3)
12x-11x+3-9=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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