2x2-x-1=x2-5x-(-1-x2)

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Solution for 2x2-x-1=x2-5x-(-1-x2) equation: 



2x^2-x-1=x2-5x-(-1-x2)

We move all terms to the left:

2x^2-x-1-(x2-5x-(-1-x2))=0

We add all the numbers together, and all the variables

2x^2-(x2-5x-(-1x^2-1))-x-1=0

We add all the numbers together, and all the variables

2x^2-(x2-5x-(-1x^2-1))-1x-1=0



We calculate terms in parentheses: -(x2-5x-(-1x^2-1)), so:

x2-5x-(-1x^2-1)

determiningTheFunctionDomain
-(-1x^2-1)+x2-5x

We add all the numbers together, and all the variables

x^2-(-1x^2-1)-5x

We get rid of parentheses

x^2+1x^2-5x+1

We add all the numbers together, and all the variables

2x^2-5x+1

Back to the equation:

-(2x^2-5x+1)



We add all the numbers together, and all the variables

2x^2-1x-(2x^2-5x+1)-1=0

We get rid of parentheses

2x^2-2x^2-1x+5x-1-1=0

We add all the numbers together, and all the variables

4x-2=0

We move all terms containing x to the left, all other terms to the right

4x=2

x=2/4

x=1/2

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