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2x^2-25x+50=5750
We move all terms to the left:
2x^2-25x+50-(5750)=0
We add all the numbers together, and all the variables
2x^2-25x-5700=0
a = 2; b = -25; c = -5700;
Δ = b2-4ac
Δ = -252-4·2·(-5700)
Δ = 46225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{46225}=215$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-215}{2*2}=\frac{-190}{4} =-47+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+215}{2*2}=\frac{240}{4} =60 $
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