5(4y+2)=71

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Solution for 5(4y+2)=71 equation: 



5(4y+2)=71

We move all terms to the left:

5(4y+2)-(71)=0

We multiply parentheses

20y+10-71=0

We add all the numbers together, and all the variables

20y-61=0

We move all terms containing y to the left, all other terms to the right

20y=61

y=61/20

y=3+1/20

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