2x2-10=-x2+8x-4

Solution for 2x2-10=-x2+8x-4 equation:

2x^2-10=-x2+8x-4

We move all terms to the left:

2x^2-10-(-x2+8x-4)=0

We add all the numbers together, and all the variables

2x^2-(-1x^2+8x-4)-10=0

We get rid of parentheses

2x^2+1x^2-8x+4-10=0

We add all the numbers together, and all the variables

3x^2-8x-6=0

a = 3; b = -8; c = -6;
Δ = b2-4ac
Δ = -82-4·3·(-6)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{34}}{2*3}=\frac{8-2\sqrt{34}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{34}}{2*3}=\frac{8+2\sqrt{34}}{6}
$