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3-1=7x^2
We move all terms to the left:
3-1-(7x^2)=0
We add all the numbers together, and all the variables
-7x^2+2=0
a = -7; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-7)·2
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{14}}{2*-7}=\frac{0-2\sqrt{14}}{-14} =-\frac{2\sqrt{14}}{-14} =-\frac{\sqrt{14}}{-7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{14}}{2*-7}=\frac{0+2\sqrt{14}}{-14} =\frac{2\sqrt{14}}{-14} =\frac{\sqrt{14}}{-7} $
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