If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+5x+6=0
a = 2; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·2·6
Δ = -23
Delta is less than zero, so there is no solution for the equation
| 9(r-√r)=-3√r-5r | | 7u-9/5=24 | | (90+8y)+34=180 | | 2(2z-2)=7(z-2 | | (X2-6x+9)-(x2-4x+4)=25 | | 16^x+1024=5x4^{x+2} | | 1/2(5-2h)=2h | | 1/8=1/8+r | | 0.81=4x-0.39 | | -12x=16x-20 | | 2/3(x)=280 | | x+2/3(x)=280 | | (x+2)(2x+4)=(x-4)(2x-3)+53 | | (15x+.8)+(6x-18)=180 | | a/5+25=50 | | (15x+1.25)+(6x-18)=180 | | 3(x+2)+2=4x+29 | | 5m+9=3m-11 | | 2x+3x=x+60 | | 61x^2+1=12x | | 7d-6-3d=18 | | 3(x+)-2(x-1)=5(x-5) | | 12=5x^2+4x | | 46+8x+-1=18x+5 | | 8-5x=4x-4 | | 5b+4-2b=16 | | (3x+2x)+(20-8)=92 | | w/4-14=22 | | 10×p=100 | | 60=3u+9 | | 4v-14=11 | | 22=u/2-8 |