(3x+2x)+(20-8)=92

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Solution for (3x+2x)+(20-8)=92 equation: 



(3x+2x)+(20-8)=92

We move all terms to the left:

(3x+2x)+(20-8)-(92)=0

determiningTheFunctionDomain
(3x+2x)-92+(20-8)=0

We add all the numbers together, and all the variables

(+5x)-92+12=0

We add all the numbers together, and all the variables

(+5x)-80=0

We get rid of parentheses

5x-80=0

We move all terms containing x to the left, all other terms to the right

5x=80

x=80/5

x=16

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