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2x^2+17x+72.25=91.25
We move all terms to the left:
2x^2+17x+72.25-(91.25)=0
We add all the numbers together, and all the variables
2x^2+17x-19=0
a = 2; b = 17; c = -19;
Δ = b2-4ac
Δ = 172-4·2·(-19)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-21}{2*2}=\frac{-38}{4} =-9+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+21}{2*2}=\frac{4}{4} =1 $
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