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3(4y-1)=5(2y-3)
We move all terms to the left:
3(4y-1)-(5(2y-3))=0
We multiply parentheses
12y-(5(2y-3))-3=0
We calculate terms in parentheses: -(5(2y-3)), so:We get rid of parentheses
5(2y-3)
We multiply parentheses
10y-15
Back to the equation:
-(10y-15)
12y-10y+15-3=0
We add all the numbers together, and all the variables
2y+12=0
We move all terms containing y to the left, all other terms to the right
2y=-12
y=-12/2
y=-6
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