2x/5=(7x-4)/10

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Solution for 2x/5=(7x-4)/10 equation: 



2x/5=(7x-4)/10

We move all terms to the left:

2x/5-((7x-4)/10)=0

We calculate fractions


20x^2/()+(-((7x-4)*5)/()=0



We calculate terms in parentheses: +(-((7x-4)*5)/(), so:

-((7x-4)*5)/(

We multiply all the terms by the denominator


-((7x-4)*5)



We calculate terms in parentheses: -((7x-4)*5), so:

(7x-4)*5

We multiply parentheses

35x-20

Back to the equation:

-(35x-20)



We get rid of parentheses

-35x+20

Back to the equation:

+(-35x+20)



We get rid of parentheses

20x^2/()-35x+20=0

We multiply all the terms by the denominator


20x^2-35x*()+20*()=0

We add all the numbers together, and all the variables

20x^2-35x*()=0

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