0.2(y+3)=0.1+0.3(1.5y-1)

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Solution for 0.2(y+3)=0.1+0.3(1.5y-1) equation: 



0.2(y+3)=0.1+0.3(1.5y-1)

We move all terms to the left:

0.2(y+3)-(0.1+0.3(1.5y-1))=0

We multiply parentheses

0.2y-(0.1+0.3(1.5y-1))+0.6=0



We calculate terms in parentheses: -(0.1+0.3(1.5y-1)), so:

0.1+0.3(1.5y-1)

determiningTheFunctionDomain
0.3(1.5y-1)+0.1

We multiply parentheses

0.3y-0.3+0.1

We add all the numbers together, and all the variables

0.3y-0.2

Back to the equation:

-(0.3y-0.2)



We get rid of parentheses

0.2y-0.3y+0.2+0.6=0

We add all the numbers together, and all the variables

-0.1y+0.8=0

We move all terms containing y to the left, all other terms to the right

-0.1y=-0.8

y=-0.8/-0.1

y=+8

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