2x/3=7/5+(4x+2)/2

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Solution for 2x/3=7/5+(4x+2)/2 equation: 


x in (-oo:+oo)

(2*x)/3 = (4*x+2)/2+7/5 // - (4*x+2)/2+7/5

(2*x)/3-((4*x+2)/2)-(7/5) = 0

(2*x)/3-((4*x+2)/2)-7/5 = 0

(-1*(4*x+2))/2+(2*x)/3-7/5 = 0

(-1*3*5*(4*x+2))/(2*3*5)+(2*2*5*x)/(2*3*5)+(-7*2*3)/(2*3*5) = 0

2*2*5*x-1*3*5*(4*x+2)-7*2*3 = 0

-40*x-42-30 = 0

-40*x-72 = 0

(-40*x-72)/(2*3*5) = 0

(-40*x-72)/(2*3*5) = 0 // * 2*3*5

-40*x-72 = 0

-40*x-72 = 0 // + 72

-40*x = 72 // : -40

x = 72/(-40)

x = -9/5

x = -9/5

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