2x=5/7+(4x+2)/2

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Solution for 2x=5/7+(4x+2)/2 equation: 


x in (-oo:+oo)

2*x = (4*x+2)/2+5/7 // - (4*x+2)/2+5/7

2*x-((4*x+2)/2)-(5/7) = 0

2*x-((4*x+2)/2)-5/7 = 0

(-1*(4*x+2))/2+2*x-5/7 = 0

(-1*7*(4*x+2))/(2*7)+(2*2*7*x)/(2*7)+(-5*2)/(2*7) = 0

2*2*7*x-1*7*(4*x+2)-5*2 = 0

-14-10 = 0

-24 = 0

-24/(2*7) = 0

-24/(2*7) = 0 // * 2*7

-24 = 0

x belongs to the empty set

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