2x/3=(3x+1)/7

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Solution for 2x/3=(3x+1)/7 equation: 



2x/3=(3x+1)/7

We move all terms to the left:

2x/3-((3x+1)/7)=0

We calculate fractions


14x^2/()+(-((3x+1)*3)/()=0



We calculate terms in parentheses: +(-((3x+1)*3)/(), so:

-((3x+1)*3)/(

We multiply all the terms by the denominator


-((3x+1)*3)



We calculate terms in parentheses: -((3x+1)*3), so:

(3x+1)*3

We multiply parentheses

9x+3

Back to the equation:

-(9x+3)



We get rid of parentheses

-9x-3

Back to the equation:

+(-9x-3)



We get rid of parentheses

14x^2/()-9x-3=0

We multiply all the terms by the denominator


14x^2-9x*()-3*()=0

We add all the numbers together, and all the variables

14x^2-9x*()=0

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