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4(5x-1)=3-2(x+1)
We move all terms to the left:
4(5x-1)-(3-2(x+1))=0
We multiply parentheses
20x-(3-2(x+1))-4=0
We calculate terms in parentheses: -(3-2(x+1)), so:We get rid of parentheses
3-2(x+1)
determiningTheFunctionDomain -2(x+1)+3
We multiply parentheses
-2x-2+3
We add all the numbers together, and all the variables
-2x+1
Back to the equation:
-(-2x+1)
20x+2x-1-4=0
We add all the numbers together, and all the variables
22x-5=0
We move all terms containing x to the left, all other terms to the right
22x=5
x=5/22
x=5/22
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