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2x-6-3x=5x(4x+2)
We move all terms to the left:
2x-6-3x-(5x(4x+2))=0
We add all the numbers together, and all the variables
-1x-(5x(4x+2))-6=0
We calculate terms in parentheses: -(5x(4x+2)), so:We get rid of parentheses
5x(4x+2)
We multiply parentheses
20x^2+10x
Back to the equation:
-(20x^2+10x)
-20x^2-1x-10x-6=0
We add all the numbers together, and all the variables
-20x^2-11x-6=0
a = -20; b = -11; c = -6;
Δ = b2-4ac
Δ = -112-4·(-20)·(-6)
Δ = -359
Delta is less than zero, so there is no solution for the equation
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