3z+15=3(3z-2)+9,z

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Solution for 3z+15=3(3z-2)+9,z equation: 



3z+15=3(3z-2)+9.z

We move all terms to the left:

3z+15-(3(3z-2)+9.z)=0



We calculate terms in parentheses: -(3(3z-2)+9.z), so:

3(3z-2)+9.z

We add all the numbers together, and all the variables

9.z+3(3z-2)

We multiply parentheses

9.z+9z-6

We add all the numbers together, and all the variables

18z-6

Back to the equation:

-(18z-6)



We get rid of parentheses

3z-18z+6+15=0

We add all the numbers together, and all the variables

-15z+21=0

We move all terms containing z to the left, all other terms to the right

-15z=-21

z=-21/-15

z=1+2/5

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