2x-5=10x+27

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Solution for 2x-5=10x+27 equation: 



2x-5=10x+27

We move all terms to the left:

2x-5-(10x+27)=0

We get rid of parentheses

2x-10x-27-5=0

We add all the numbers together, and all the variables

-8x-32=0

We move all terms containing x to the left, all other terms to the right

-8x=32

x=32/-8

x=-4

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