2x-5(x-3)=-7+4x+8

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Solution for 2x-5(x-3)=-7+4x+8 equation: 



2x-5(x-3)=-7+4x+8

We move all terms to the left:

2x-5(x-3)-(-7+4x+8)=0

We add all the numbers together, and all the variables

2x-5(x-3)-(4x+1)=0

We multiply parentheses

2x-5x-(4x+1)+15=0

We get rid of parentheses

2x-5x-4x-1+15=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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