2x-5(4x-4)=5-2(-5-x)

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Solution for 2x-5(4x-4)=5-2(-5-x) equation: 



2x-5(4x-4)=5-2(-5-x)

We move all terms to the left:

2x-5(4x-4)-(5-2(-5-x))=0

We add all the numbers together, and all the variables

2x-5(4x-4)-(5-2(-1x-5))=0

We multiply parentheses

2x-20x-(5-2(-1x-5))+20=0



We calculate terms in parentheses: -(5-2(-1x-5)), so:

5-2(-1x-5)

determiningTheFunctionDomain
-2(-1x-5)+5

We multiply parentheses

2x+10+5

We add all the numbers together, and all the variables

2x+15

Back to the equation:

-(2x+15)



We add all the numbers together, and all the variables

-18x-(2x+15)+20=0

We get rid of parentheses

-18x-2x-15+20=0

We add all the numbers together, and all the variables

-20x+5=0

We move all terms containing x to the left, all other terms to the right

-20x=-5

x=-5/-20

x=1/4

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