-2/3(-5x-18)+6-7x=2(-x+4)

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Solution for -2/3(-5x-18)+6-7x=2(-x+4) equation: 



-2/3(-5x-18)+6-7x=2(-x+4)

We move all terms to the left:

-2/3(-5x-18)+6-7x-(2(-x+4))=0



Domain of the equation: 3(-5x-18)!=0

x∈R



We add all the numbers together, and all the variables

-2/3(-5x-18)-7x-(2(-1x+4))+6=0

We add all the numbers together, and all the variables

-7x-2/3(-5x-18)-(2(-1x+4))+6=0

We multiply all the terms by the denominator


-7x*3(-5x-18)-((2(-1x+4)))*3(-5x-18)+6*3(-5x-18)-2=0



We calculate terms in parentheses: -((2(-1x+4)))*3(-5x-18), so:

(2(-1x+4)))*3(-5x-18

We add all the numbers together, and all the variables

-5x+(2(-1x+4)))*3(-18

Back to the equation:

-(-5x+(2(-1x+4)))*3(-18)



Wy multiply elements

-21x^2(--(-5x+(2(-1x+4)))*3(-18)+18x(--2=0

We use the square of the difference formula

-21x^2(+(-5x+(2(-1x+4)))*3(-18)+18x(+2=0

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