If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x-4x^2=0
a = -4; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-4)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-4}=\frac{-4}{-8} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-4}=\frac{0}{-8} =0 $
| 2{2x+5}=7x+7-3x+3 | | (9x)=(6x+30) | | 12(2x+11)=12(2x+12 | | 21924=-812x3 | | -3/8f+-1/2=6(-1/16f-3) | | -4.9t^2+6t+10=0 | | 3(5x-2)=-39 | | 2x+62=5x-22 | | (x)=22 | | 5+3.50x=6+2.25x | | 5x-15+4x-3=180 | | -2/5+x/5=2 | | 2(b+7)=32 | | v+1.83=6.31 | | –9m=–10m−10 | | —(3-6x)=-(-6x+3) | | 9|7x−3|=−90 | | 9(7x−3)=−90 | | 1+3r=16 | | (-x+2)=5x+3x-11 | | -1/2r+6=3-2r | | 8x-12+7x+27=90 | | 5x+10+2x+10+110=360 | | 2(x+5)/3=16 | | 5x+10+2x+10+110=110 | | 2y2+8y-10=0 | | 2/3(6x-9)-2x=20 | | 12(x+5)=18x | | 2(3x+7)=x+10+5+4 | | 8=3m+5+4 | | 3y-8=5y+10y= | | x/12=2.7 |