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2x-4+x=5+x2
We move all terms to the left:
2x-4+x-(5+x2)=0
We add all the numbers together, and all the variables
-(+x^2+5)+2x+x-4=0
We add all the numbers together, and all the variables
-(+x^2+5)+3x-4=0
We get rid of parentheses
-x^2+3x-5-4=0
We add all the numbers together, and all the variables
-1x^2+3x-9=0
a = -1; b = 3; c = -9;
Δ = b2-4ac
Δ = 32-4·(-1)·(-9)
Δ = -27
Delta is less than zero, so there is no solution for the equation
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