2x-4+2x=4(4x-2)+2

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Solution for 2x-4+2x=4(4x-2)+2 equation: 



2x-4+2x=4(4x-2)+2

We move all terms to the left:

2x-4+2x-(4(4x-2)+2)=0

We add all the numbers together, and all the variables

4x-(4(4x-2)+2)-4=0



We calculate terms in parentheses: -(4(4x-2)+2), so:

4(4x-2)+2

We multiply parentheses

16x-8+2

We add all the numbers together, and all the variables

16x-6

Back to the equation:

-(16x-6)



We get rid of parentheses

4x-16x+6-4=0

We add all the numbers together, and all the variables

-12x+2=0

We move all terms containing x to the left, all other terms to the right

-12x=-2

x=-2/-12

x=1/6

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