2x-4(x-5)=-8+3x-12

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Solution for 2x-4(x-5)=-8+3x-12 equation: 



2x-4(x-5)=-8+3x-12

We move all terms to the left:

2x-4(x-5)-(-8+3x-12)=0

We add all the numbers together, and all the variables

2x-4(x-5)-(3x-20)=0

We multiply parentheses

2x-4x-(3x-20)+20=0

We get rid of parentheses

2x-4x-3x+20+20=0

We add all the numbers together, and all the variables

-5x+40=0

We move all terms containing x to the left, all other terms to the right

-5x=-40

x=-40/-5

x=+8

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