3(3-z)-(3+z)=-10

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Solution for 3(3-z)-(3+z)=-10 equation: 



3(3-z)-(3+z)=-10

We move all terms to the left:

3(3-z)-(3+z)-(-10)=0

We add all the numbers together, and all the variables

3(-1z+3)-(z+3)-(-10)=0

We add all the numbers together, and all the variables

3(-1z+3)-(z+3)+10=0

We multiply parentheses

-3z-(z+3)+9+10=0

We get rid of parentheses

-3z-z-3+9+10=0

We add all the numbers together, and all the variables

-4z+16=0

We move all terms containing z to the left, all other terms to the right

-4z=-16

z=-16/-4

z=+4

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