2x-4(x-5)=-8+2x+16

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Solution for 2x-4(x-5)=-8+2x+16 equation: 



2x-4(x-5)=-8+2x+16

We move all terms to the left:

2x-4(x-5)-(-8+2x+16)=0

We add all the numbers together, and all the variables

2x-4(x-5)-(2x+8)=0

We multiply parentheses

2x-4x-(2x+8)+20=0

We get rid of parentheses

2x-4x-2x-8+20=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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