4(2x-7)-3=4(x-5)+5

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Solution for 4(2x-7)-3=4(x-5)+5 equation: 



4(2x-7)-3=4(x-5)+5

We move all terms to the left:

4(2x-7)-3-(4(x-5)+5)=0

We multiply parentheses

8x-(4(x-5)+5)-28-3=0



We calculate terms in parentheses: -(4(x-5)+5), so:

4(x-5)+5

We multiply parentheses

4x-20+5

We add all the numbers together, and all the variables

4x-15

Back to the equation:

-(4x-15)



We add all the numbers together, and all the variables

8x-(4x-15)-31=0

We get rid of parentheses

8x-4x+15-31=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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