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2x-4(x-3)=3(x-6)
We move all terms to the left:
2x-4(x-3)-(3(x-6))=0
We multiply parentheses
2x-4x-(3(x-6))+12=0
We calculate terms in parentheses: -(3(x-6)), so:We add all the numbers together, and all the variables
3(x-6)
We multiply parentheses
3x-18
Back to the equation:
-(3x-18)
-2x-(3x-18)+12=0
We get rid of parentheses
-2x-3x+18+12=0
We add all the numbers together, and all the variables
-5x+30=0
We move all terms containing x to the left, all other terms to the right
-5x=-30
x=-30/-5
x=+6
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