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2x-3x+10=5-(x-5)
We move all terms to the left:
2x-3x+10-(5-(x-5))=0
We add all the numbers together, and all the variables
-1x-(5-(x-5))+10=0
We calculate terms in parentheses: -(5-(x-5)), so:We get rid of parentheses
5-(x-5)
determiningTheFunctionDomain -(x-5)+5
We get rid of parentheses
-x+5+5
We add all the numbers together, and all the variables
-1x+10
Back to the equation:
-(-1x+10)
-1x+1x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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