74=4x+3(4x-2)

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Solution for 74=4x+3(4x-2) equation: 



74=4x+3(4x-2)

We move all terms to the left:

74-(4x+3(4x-2))=0



We calculate terms in parentheses: -(4x+3(4x-2)), so:

4x+3(4x-2)

We multiply parentheses

4x+12x-6

We add all the numbers together, and all the variables

16x-6

Back to the equation:

-(16x-6)



We get rid of parentheses

-16x+6+74=0

We add all the numbers together, and all the variables

-16x+80=0

We move all terms containing x to the left, all other terms to the right

-16x=-80

x=-80/-16

x=+5

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